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A comprehensive regex for phone number validation
Validate phone number with JavaScript

I'm trying to write a regular expression to validate US phone number of format (123)123-1234 -- true 123-123-1234 -- true

every thing else in not valid.

I came up something like 

 ^\(?([0-9]{3}\)?[-]([0-9]{3})[-]([0-9]{4})$

But this validates, 123)-123-1234 (123-123-1234

which is NOT RIGHT.

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  • 17
    I think it's a lot friendlier to let people type in their phone numbers any way they want. Just strip out non-digits and insist on 10 digits being left after that. Commented Mar 19, 2012 at 19:14
  • 1
    This may be a duplicate, but please link to the previous answers before marking the post. Commented Mar 24, 2015 at 12:23

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The easiest way to match both

^\([0-9]{3}\)[0-9]{3}-[0-9]{4}$

and

^[0-9]{3}-[0-9]{3}-[0-9]{4}$

is to use alternation ((...|...)): specify them as two mostly-separate options:

^(\([0-9]{3}\)|[0-9]{3}-)[0-9]{3}-[0-9]{4}$

By the way, when Americans put the area code in parentheses, we actually put a space after that; for example, I'd write (123) 123-1234, not (123)123-1234. So you might want to write:

^(\([0-9]{3}\) |[0-9]{3}-)[0-9]{3}-[0-9]{4}$

(Though it's probably best to explicitly demonstrate the format that you expect phone numbers to be in.)

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12 Comments

The above expression gives success for (000) 000-0000 how can we avoid that?
@HaBo: Why would we want to avoid that?
since it is not a valid phone number.
@HaBo: A regex can't detect valid phone numbers, only validly formatted phone numbers. That said, no U.S. area codes begin with 0 or 1, so if you wanted, you could change the initial [0-9]{3} to [2-9][0-9][0-9].
Yeah I was looking for such thing. So will ^(([2-9]{1}[0-9]{2}) |[0-9]{3}-)[0-9]{3}-[0-9]{4}$ works for (200) 000-0000
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