syntax error verilog code

Question

this sub-code that read the selection line s4-s1 and take the summation of a,b in the selection line =0000, When running this code in ISE project negotiator it gives syntax error tell " Syntax error near "=" " in the line z=0 in the if statement

can you tell me why ?

module one1(a,b,s1,s2,s3,s4,f );
  input s1,s2,s3,s4;
  input [3:0] a,b;
  output reg [3:0] f;

  reg  z,n,c;

  //0000

  if ({s4,s3,s2,s1} == 4'b0000)
  begin
    assign {c,f}= a+b; 
    if (f==0) 
      z=1;         //here is the error 
    else z=0;
    n=f[3];
  end

endmodule

crgrace · Accepted Answer · 2015-04-11 17:28:54Z

4

Two problems:

You need to wrap an always block around your combinational logic. Something like always @* begin

then put your if statement in there.

You can't assign a wire inside an always block. you need a reg.

answered Apr 11, 2015 at 17:28

crgrace

1,91012 silver badges8 bronze badges

\$\begingroup\$ "you need a reg."... or move the assign statement outside the if block. \$\endgroup\$

The Photon
– The Photon

2015-04-11 18:44:10 +00:00
Commented Apr 11, 2015 at 18:44

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