Rails - Display a different form for the same action based on the url

Question

I have a simple Client model with some fields and a basic form. The url to access it is /clients/new, that leads to clients#new method. What I need to do is create a new route to resellers, that will lead to the same method and the same form, but with some new fields, like the reseller's name.

Example: url /reseller/clients/new leads to the method clients#new and display a new cell with new inputs for the new form.

I created a method that checks the url and sets a session if the route has "reseller" in it, so my cell can handle if the new fields will be displayed or not. But this is leading me to problems regarding model validations, since if the new fields are displayed in the view, theire presence is true. I would have to access my sessions inside the model in order to create a proper validation, and that does not sound as the right path.

I wonder how can I achieve my goal within a proper way?

Thanks in advance.

i would recommend you to split it up in different routes and controllers — BvuRVKyUVlViVIc7
– BvuRVKyUVlViVIc7, Commented Aug 17, 2012 at 13:23

Lucas Nogueira · Accepted Answer · 2012-08-17 14:13:02Z

1

Solved.

For this I created a new model called Reseller. With that, the model Client has accepts_nested_attributes_for :reseller. This way I can render the form in my cell for the Reseller model and set all the fields inside it with :presence => true, with no need of a conditional statement. If the url has "reseller", the cell will render the form and the validation will happen.

answered Aug 17, 2012 at 14:13

Lucas Nogueira

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