regular expression with php to extract

Question

I need a regular expression what would search at the beginning of my string if there is a number followed a percent sign and extract it.

$string = "20% - some text";

preg_match('/^[0-9]+%$/',$string);

should return 20%

elboletaire · Accepted Answer · 2012-09-09 00:14:57Z

2

You should use the $matches argument:

$string = "20% - some text";
$matches = array();
if (preg_match('/^([0-9]+%)/', $string, $matches)) {
     print_r($matches);
}

answered Sep 9, 2012 at 0:12

elboletaire

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