Django Celery application - No module named celery error

Question

I have created a django-celery application as in the tutorial at:

http://docs.celeryproject.org/en/master/django/first-steps-with-django.html

Everything works fine when I run it without application parameter as in:

$ python manage.py celery worker -l info

but I can't start it at all with the application parameter, as in:

$ python manage.py celery worker -A myapp -l info

where myapp is the name given to the application when I created the project with:

$ python manage.py startapp myapp

The error that I am getting is:

ImportError: No module named celery

Does anyone know why this happens and how to solve it?

-A argument is for celery applications, not for Django applications... They are not used by django-celery at the moment. — asksol
– asksol, Commented Apr 9, 2013 at 14:13
ah, I didn't know that. Thanks for the answer. But then how can I run this? — Clara
– Clara, Commented Apr 9, 2013 at 14:49
Celery 3.1 will support django from scratch (but does not have all of the features from django-celery, e.g no database result backend and no database periodic task scheduler, but you can still use djcelery on top to get that) — asksol
– asksol, Commented Apr 10, 2013 at 10:43
Example using celery with django in celery 3.1 (dev): github.com/celery/celery/tree/master/examples/django — asksol
– asksol, Commented Apr 10, 2013 at 10:44

mafrosis · Accepted Answer · 2014-04-10 00:43:31Z

17

Edit April 2014:

The Celery docs have been updated for 3.1; the below solution is now outdated, see:

http://docs.celeryproject.org/en/master/django/first-steps-with-django.html

By default, celery searches for a module named celery.py to find its configuration. You can get celery to use a different name than celery.py by specify it on the app argument - in this example, we'll look for celery config in settings.py:

python manage.py celery worker --app=myapp.settings

When using django-celery you can either use the above call to start celery, or do as I originally did and create a celery.py in my application package myapp:

from settings import celery

My Django settings.py contains the normal celery config:

from celery import Celery

celery = Celery(broker="amqp://guest:[email protected]:5672//")

celery.conf.update(
    CELERY_DEFAULT_QUEUE = "myapp",
    CELERY_DEFAULT_EXCHANGE = "myapp",
    CELERY_DEFAULT_EXCHANGE_TYPE = "direct",
    CELERY_DEFAULT_ROUTING_KEY = "myapp",
)

Then run the celery worker like this:

python manage.py celery worker --app=myapp

Just for clarity's sake, here's my full application structure:

myproject/
    manage.py
    myapp/
        __init__.py
        settings.py
        celery.py

edited Apr 10, 2014 at 0:43

answered Apr 10, 2013 at 0:05

mafrosis

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6 Comments

Milimetric Over a year ago

i'm voting +1 because this helped me realize that celery config is a bit of black magic and I have to be careful. But you should edit your answer because it's inconsistent. Why do you have a celery.py file if you're setting up celery in settings.py? Or did you mean to say you're setting it up in celery.py?

mafrosis Over a year ago

Just updated the answer, based on a better understanding I now have :) @Milimetric I have a celery.py file which imports settings.py, as that is what celery looks for by default.

Milimetric Over a year ago

If your code is working, and it's open source, a link would be great. Thanks for the edit.

mafrosis Over a year ago

@Milimetric Sorry I don't have a link to a specific example. I use Flask on open-source projects.. Can you not get the above working?

Milimetric Over a year ago

no, i'm having some crazy unrelated problem. I have from celery import Celery in a folder along with what's probably bad configuration. Here's the crazy part: when I try to run any other working examples, it goes to that other folder and says ImportError: cannot import name Celery

|

Raj · Accepted Answer · 2015-02-14 02:26:56Z

1

Be sure you're trying to start the celery worker from a directory that has access to the celery module. In my case I was trying to start the worker from the app directory rather than the project.

answered Feb 14, 2015 at 2:26

Raj

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