Python client server to send a file Beginner Error

Question

I am trying to do simple code to send file from the client to the server after saving in t some data. I am a beginner so I can't figure where the problem is or what is the missing function or line in my code

The Server :

import socket

server_socket = socket.socket()
server_socket.bind(('0.0.0.0', 8000))
server_socket.listen(0)
BUFFER_SIZE = 1024
conn, addr = server_socket.accept()
print ('Got connection from', addr)
while 1:
    data = conn.recv(BUFFER_SIZE)
    if not data: 
        break
    fileREC=open (data , 'rb')

The Client

import socket
client_socket = socket.socket()
client_socket.connect(("192.168.1.4", 8000))
BUFFER_SIZE = 1024
TextFile= open ("TextFile","w")
TextFile.write("Here is the file")
TextFile.write("Writing data")
TextFile.close()
f=open (TextFile , 'wb')
print ("Writing the file to binart ")
client_socket .send(f)
print ("Data Sent")

The Error

  ERROR:Traceback (most recent call last):
  File "tenmay.py", line 5, in <module>
   client_socket.connect(("192.168.1.4", 8000))
  File "/usr/lib/python2.7/socket.py", line 224, in meth
  return getattr(self._sock,name)(*args)
  socket.error: [Errno 111] Connection refused

Are you sure that the server has 192.168.1.4 ip? Can you ping this address? — ρss
– ρss, Commented May 10, 2014 at 22:05

user3286261 · Accepted Answer · 2014-05-10 22:32:18Z

1

Send the contents of the file not the filehandle:

f=open ("TextFile", 'rb')
client_socket.send(f.read())

The second time the client runs the server is waiting to recv data because the accept() command is outside of the loop.

The client could repeatedly send data from a loop, but not if the program ends and has to be restarted.

edited May 10, 2014 at 22:32

answered May 10, 2014 at 22:23

user3286261

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