hashtables and arrays powershell

Question

I need to store in Item of hashtable 2 int variables. But cannot undestand how to store it:

    $hash = @{}
    if($hash.contains($name) -eq $False){
        $value = 1
        $arr = @($my_var;$value)
        $hash.add($name,$arr)
    }else{
        $value = $hash.item($name)
        $value[1]++ #PROBLEM HERE
        $hash.item($name)[0] = $my_var
        $hash.item($name)[1] = $value
    }

Problem is that $value[1] not exists(Note1), $value[0] contains also $my_var and $value with space.

Note1 - The '++' operator works only on numbers. The operand is a 'System.Object[]'.

Frode F. · Accepted Answer · 2014-07-14 14:02:03Z

I'm not sure if I understand your question. Do you want to update the int-value? If so, your problem is that you overwrite the int-value that was stored in $hash.item($name)[1] with not just an int, but the whole array. You're essentially creating this:

$hash.item($name) = @($my_var, $value, @($my_var, $value+1))

You could fix this by updating this line:

$hash.item($name)[1] = $value

to

$hash.item($name)[1] = $value[1]

If $my_var is always the same value, you could clean it up by replacing the whole item:

$my_var = "test"
$name = "nametest"
#$hash = @{}   #ran this first time to create ht before commenting it out to avoid overwriting the ht

if($hash.Contains($name) -eq $False){
    $value = 1
    $arr = @($my_var;$value)
    $hash.add($name,$arr)
}else{
    $value = $hash.item($name)
    $value[1]++
    $hash.item($name) = $value
}

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