I am trying to overload my constructor for TypeScript Class
constructor(a: T[])
constructor(...a: T[]) {
a.forEach(e => {
//do something with e
});
}
Why does the compiler complain about the above? And any ideas how to fix it?
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1Please add the error message to your questionLucas Moulin– Lucas Moulin2016-03-20 15:42:57 +00:00Commented Mar 20, 2016 at 15:42
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1 Answer
Provided code snippet is not a class. Assuming it is actually wrapped in class. This should work correctly (also in runtime):
class A<T> {
constructor(a: T[]); // first overload
constructor(...a: T[]); // second overload
constructor(a) { // implementation (should implement all overloads)
a = arguments.length === 1 ? a : Array.prototype.slice.call(arguments);
a.forEach(e => {
//do something with e
console.log(e);
});
}
}
var strings = new A<string>(['a']);
var numbers = new A<number>(1, 2, 4);
Read more in Handbook.
3 Comments
Peter
Thanks. I expected the reader to figure out it was wrapped in a class when I said so.
Simon_Weaver
am I missing the magic syntax for using
private and ... in a constructor or is it not possible? constructor(private ...steps: Step[])
ahz
Not sure, but I'd guess it is not supported. At least it does not feel right to me to accept multiple parameters as private field.