how to write javascript inside php tag

Question

I am trying to write a javascript inside php tags my javascpript is here

<script>  
    $('#img').attr("src","getImage.php?id="+);
    $('#img').show();
</script>

and what I am doing is here

   <?php
    echo "<script>";  
    echo " $('#img').attr(\"src\",\"getImage.php?id=\"+1); ";
    echo " $('#img').show(); ";
    echo "</script>";
    ?>

what is wrong here?

Possible duplicate of how to write javascript code inside php — muya.dev
– muya.dev, Commented Aug 20, 2016 at 22:21
You need to echo the whole JS inside the php tag because PHP doesn't know anything of what you're doing with it. Like, <?php echo "<script> your code here </script>"; ?> — Raktim Biswas
– Raktim Biswas, Commented Aug 20, 2016 at 22:34

Diogo Eichert · Accepted Answer · 2016-08-20 22:43:05Z

1

Your script tag is just like any other HTML tag, just close your PHP tag before opening it:

?>

<script>  
    $('#img').attr("src", "getImage.php?id=" + 1);
    $('#img').show();
</script>

<?php

answered Aug 20, 2016 at 22:43

Diogo Eichert

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Comments

GeekWithGlasses · Accepted Answer · 2016-08-20 22:39:49Z

0

what I was doing wrong is , I was echoing the js in parts. What I needed to was something like this

    <?php
    echo " <script>  
    $('#img').attr(\"src\",\"getImage.php?id=\"+2);
    $('#img').show();
    </script> ";
    ?>

whole js in just 1 peice is the key here.

answered Aug 20, 2016 at 22:39

GeekWithGlasses

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1 Comment

Mostafa Over a year ago

closing the PHP tag and reopen it will be easy for long codes

francis94c · Accepted Answer · 2016-08-20 22:59:05Z

I'm guessing the reason you are echoing javascript via php is that u want to be able to generate dynamically the number you add to the end of the image source/src tag. you can do it as follows...

As far as your php file is saved with extension of '.php' you can do this without errors:

<?php $n = 2; //Declaration of n ?>
<script>
$("#img").attr("src", <?php echo "\"getImage.php?id=$n\"" ?>);
$("#img").show();
</script>

And that is it, just use the php open and closing tag where u need to output something dynamic... other than that, leave pure javascript out side to avoid confusion. Make sure u provided a link to jquery library as well as i can see that from your syntax u intend to use jquery. hope this helps. :-)

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