Python how to delete a specific value from a dictionary key with multiple values?

Question

I have a dictionary with multiple values per key and each value has two elements (possibly more). I would like to iterate over each value-pair for each key and delete those values-pairs that meet some criteria. Here for instance I would like to delete the second value pair for the key A; that is: ('Ok!', '0'):

myDict = {'A': [('Yes!', '8'), ('Ok!', '0')], 'B': [('No!', '2')]}

to:

myDict = {'A': [('Yes!', '8')], 'B': [('No!', '2')]}

I can iterate over the dictionary by key or value, but can't figure out how I delete a specific value.

you can use remove. for example myDict['A'].remove( ('Ok!', '0') ) — Copperfield
– Copperfield, Commented Sep 6, 2016 at 13:48

Em L · Accepted Answer · 2016-09-06 13:48:53Z

5

The code like this:

myDict = {'A': [('Yes!', '8'), ('Ok!', '0')], 'B': [('No!', '2')]}
for v in myDict.values():
    if ('Ok!', '0') in v:
        v.remove(('Ok!', '0'))
print(myDict)

answered Sep 6, 2016 at 13:48

Em L

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1 Comment

ShadowRanger Over a year ago

Minor note: If the lists might be long and removals semi-common, it would be better to do try: v.remove(('Ok!', '0')), except ValueError: pass, so you're only iterating the list once, not once to check, and a second time to remove. Also, if you're on Python 2, use .itervalues() or .viewvalues() over .values(), to avoid creating an unnecessary temporary list of the values; on Py2, .values() is equivalent to Py2.7's .viewvalues(), so it avoids the temporaries automatically.

Shivam · Accepted Answer · 2020-02-14 13:45:17Z

0

You can also do like this:

myDict = {'A': [('Yes!', '8'), ('Ok!', '0')], 'B': [('No!', '2')]}
del myDict['A'][1]
print(myDict)

Explanation :

myDict['A'] - It will grab the Value w.r.t Key A

myDict['A'][1] - It will grab first index tuple

del myDict['A'][1] - now this will delete that tuple

edited Feb 14, 2020 at 13:45

answered Feb 14, 2020 at 13:38

Shivam

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Comments

Amin Ba · Accepted Answer · 2019-02-16 04:07:04Z

-3

myDict = {'A': [('Yes!', '8'), ('Ok!', '0')], 'B': [('No!', '2')]}
for v in myDict.values():
    for x in v:
        if x[0] == 'Ok!' and x[1] == '0':
            v.remove(x)
print(myDic)

edited Feb 16, 2019 at 4:07

answered Feb 15, 2019 at 19:54

Amin Ba

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3 Comments

Amin Ba Over a year ago

This is a minor change to the response of @Em L . With this modification, it is possible to check for a condition on the first element of a member of all values.

Heikki Over a year ago

The element to be found was value pair ('Ok!', '0'). If checking just first element for 'Ok!', also other tuplets like ('Ok!', '1') will match. Therefore, this is not an answer to the question.

Nick Over a year ago

@AminBa rather than trying to explain your answer in the comments, please use the edit button under your answer and modify it to include the information that you have put in the comments (and then delete the comments)

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