c++ - Convert an int array of 8 positions to char

Question

I have an int array of 8 positions representing 8 bits.

int zBits[8]={0, 1, 1, 1, 1, 0, 1, 0};

zBits array is the character "z" in bits ("7a" in hex) (http://www.utf8-chartable.de/).

How can I convert this int array (zBits) in the "z" char using c++?

Greg Hewgill · Accepted Answer · 2016-10-11 00:49:11Z

4

The most straightforward way to do this is directly:

char z = (zBits[7]     ) |
         (zBits[6] << 1) |
         (zBits[5] << 2) |
         (zBits[4] << 3) |
         (zBits[3] << 4) |
         (zBits[2] << 5) |
         (zBits[1] << 6) |
         (zBits[0] << 7);

If you like, you can reformulate this into a loop which will be slightly shorter.

answered Oct 11, 2016 at 0:49

Greg Hewgill

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