Aligning Columns in matplotlib.pyplot.figtext

Question

(towns_n and Towns are two arrays each with 50 numbers and names respectively)

count = 0 
for number,town in zip(towns_n,Towns):
    textString += (number +'.'+ town).ljust(35)
    count += 1
    if count == 6:
        count = 0
        textString += '\n' 
plt.figtext(0.13,0.078,textString)

My problem is that I want to plot 6 columns.

And if I print my string it looks exactly as expected, it looks like 6 aligned columns. But if I plot it along my other image it doesn't look aligned at all.
I don't think it matters but my other image is a map usign basemap. I am plotting this string just below my map.

What I am getting

Edit: You can try this to generate 50 random strings and numbers so that you don't need the actual list of towns.

def id_generator(size=6, chars=string.ascii_uppercase + string.digits):
    return ''.join(random.choice(chars) for _ in range(size))

Towns=[]
towns_n=[]

for i in range(50):
    string = id_generator()
    Towns.append(string);
    towns_n.append(str(i))

Can you please provide an image of what you are talking about here? Also, provide a minimal reproducible example of the issue. — ImportanceOfBeingErnest
– ImportanceOfBeingErnest, Commented Nov 2, 2017 at 23:33
I guess what you are trying to do requires a monospaced font. Did you consider using one? Otherwise you would need to create 6 single text elements (one for each "column"). Again, provide a minimal reproducible example to get an answer (or are you expecting someone to type in all cities in the UK?). — ImportanceOfBeingErnest
– ImportanceOfBeingErnest, Commented Nov 2, 2017 at 23:48
Thanks, I think I am about to give up and do what you suggest about the 6 strings. I have added something in the last edit so that you can get 50 random words and numbers. — Daniel Duque
– Daniel Duque, Commented Nov 3, 2017 at 0:30

ImportanceOfBeingErnest · Accepted Answer · 2017-11-03 00:51:23Z

As said in the comments, one solution would be to use a monospaced font.

plt.figtext(..., fontname="DejaVu Sans Mono")

Example:

import random
import string
import matplotlib.pyplot as plt

def id_generator(size=6, chars=string.ascii_uppercase + string.digits):
    return ''.join(random.choice(chars) for _ in range(size))

Towns=[]
towns_n=[]

for i in range(50):
    string = id_generator()
    Towns.append(string);
    towns_n.append(str(i))


count = 0 
textString =""
for number,town in zip(towns_n,Towns):
    textString += (number +'.'+ town).ljust(12)
    count += 1
    if count == 6:
        count = 0
        textString += '\n'

fig = plt.figure()
fig.add_subplot(111)
fig.subplots_adjust(bottom=0.5)
plt.figtext(0.05,0.078,textString, fontname="DejaVu Sans Mono")

plt.show()

The other option is to create each column separately:

import random
import string
import matplotlib.pyplot as plt

def id_generator(size=6, chars=string.ascii_uppercase + string.digits):
    return ''.join(random.choice(chars) for _ in range(size))

Towns=[]
towns_n=[]

for i in range(50):
    string = id_generator()
    Towns.append(string);
    towns_n.append(str(i))


fig = plt.figure()
fig.add_subplot(111)
fig.subplots_adjust(bottom=0.5)

space = 0.05
left = 0.05
width= 0.15
for i in range(6):
    t = [towns_n[i::6][j] + ". " + Towns[i::6][j] for j in range(len(towns_n[i::6]))]
    t = "\n".join(t)
    plt.figtext(left+i*width,0.35,t, va="top", ha="left")

plt.show()

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