The content of my text file is:
5 7 6 6 15
4 3
When I do
fs.open('path',mode='rb').read()
I get
b'5 7 6 6 15\r\n4 3'
But because I want it to compare to string output
5 7 6 6 15
4 3
I want to do this comparison like :
if fs.open('path',mode='rb').read() == output
print("yes")
How should I convert it in way that line breaks space everything is maintained?
PS: output is just the string that I am getting through json.
Using Python 3, fs.open('path',mode='rb').read() yields a bytes object, moreover containing a carriage return (windows text file)
(and using Python 2 doesn't help, because of this extra \r which isn't removed because of binary mode)
You're comparing a bytes object with a str object: that is always false.
Moreover, it's unclear if the output string has a line termination on the last line. I would open the file in text mode and strip blanks/newline the end (the file doesn't seem to contain one, but better safe than sorry):
with open('path') as f:
if f.read().rstrip() == output.rstrip():
Change the read mode from rb to r: rb gives back binary, r puts out text.
