Variable in array and value separed with comma

Question

My code is:

$arr = array(1,2,3);
foreach ($arr as $key => $value) 
{
  $resultstr[] = "FIND_IN_SET (" .$value. ", Dotazioni) > 0";   
}
$dotazioni_camera = implode(" and ",$resultstr);
echo($dotazioni_camera);

Result is:

FIND_IN_SET (1, Dotazioni) > 0 and FIND_IN_SET (2, Dotazioni) > 0 and FIND_IN_SET (3, Dotazioni) > 0

This is correct!! But if i try to change Arr from

 $arr = array(1,2,3);

To

 $arr = array($var);

the result change in:

FIND_IN_SET (1,2,3, Dotazioni) > 0

I think that variable convert integer value separeted by comma in a string value. I looked for a possible solution but I did not find anything. I hope you can help me.

what does $var has ?

Arun Kumaresh
– Arun Kumaresh

2017-12-21 12:01:54 +00:00
Commented Dec 21, 2017 at 12:01 — Arun Kumaresh
– Arun Kumaresh, Commented Dec 21, 2017 at 12:01
can you please share your $var value?

Soubhagya Kumar Barik
– Soubhagya Kumar Barik

2017-12-21 12:02:04 +00:00
Commented Dec 21, 2017 at 12:02 — Soubhagya Kumar Barik
– Soubhagya Kumar Barik, Commented Dec 21, 2017 at 12:02

Nigel Ren · Accepted Answer · 2017-12-21 12:06:43Z

2

If you have

$var = '1,2,3';

When you call

$arr = array($var);

This is an array of 1 value - 1,2,3. If you want to have an array of values 1, 2 and 3, you will have to do something like...

$var = '1,2,3';
$arr = explode(",", $var);

answered Dec 21, 2017 at 12:06

Nigel Ren

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