php gd script not saving image properly

Question

I've got this script, which only saves the image at $image, and not the image at $newimage_2. Help?

<?php


$newimage_1 = imagecopymerge($image, $watermark, $dest_x, $dest_y, 0, 0, $watermark_width, $watermark_height, $opacity);
$newimage_2 = imagecreatefromjpeg($newimage_1);

// print image to screen
header("content-type: image/jpeg");   
imagejpeg($image);
imagejpeg($newimage_2);
imagedestroy($image);  
imagedestroy($watermark);
imagedestroy($newimage_2);

?>

Not a solution to your problem, but imagecopymerge returns a bool and imagecreatefromjpeg takes a string. — alexn
– alexn, Commented Jan 26, 2011 at 15:19
As alexn wrote imagecreatefromjpeg takes string (a "Path to the JPEG image") and it seems that your $newimage_1 is bool. — Marcin
– Marcin, Commented Jan 26, 2011 at 15:28
also, two imagejpeg() calls in one requests isn't going to work ... — etarion
– etarion, Commented Jan 26, 2011 at 15:32

FeRtoll · Accepted Answer · 2011-01-26 15:37:23Z

1

$source_file_path=$_FILES["image"]["tmp_name"];
$src = imagecreatefromjpeg($source_file_path);
list($width,$height)=getimagesize($source_file_path);
$newwidth=540;
$newheight=round(($height/$width)*$newwidth);
$tmp=imagecreatetruecolor($newwidth,$newheight);
imagecopyresampled($tmp,$src,0,0,0,0,$newwidth,$newheight,$width,$height);
$target_file_path = "images/".$filewhereyouwanttosaveit;

$watermark = imagecreatefrompng('imgs/copyright.png');
$watermarkwidth = imagesx($watermark);
$watermarkheight = imagesy($watermark);
$startwidth = ($newwidth - $watermarkwidth);
$startheight = ($newheight - $watermarkheight);
imagecopy($tmp,$watermark,$startwidth,$startheight,0,0,$watermarkwidth,$watermarkheight);
imagegif($tmp,$target_file_path);

you probably dont need the resizing but code may help you...

imagegif or jpg or png or some else

answered Jan 26, 2011 at 15:37

FeRtoll

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1 Comment

Tom Granot Over a year ago

Thanks Man-exactly what i wanted!

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