How to use optional route parameters properly with Laravel 5.6?

Question

I am trying to create an API with Laravel 5.6, however, it seems to me that it's not possible to use optional route parameters before/after the parameter.

I'd like to achieve the following:

Route::get('api/lists/{id?}/items', 
[
    'as'    => 'api/lists/items/get', 
    'uses'  => 'ListsController@getListItems'
]);

With the above scenario, if I'm trying to visit api/lists/1/items it shows the page. On the other hand, if I'm trying to visit api/lists/items it says that the page is not found.

What I basically want is if there's no List ID specified, Laravel should fetch all the List ID's items, otherwise it should only fetch the specific ID's items.

Q: How is it possible to the optional parameter in between the 'route words'? Is it even possible? Or is there an alternative solution to this?

Bert H · Accepted Answer · 2018-06-27 09:42:23Z

6

As far as I know, it's not possible to use optional parameters in the middle of your url.

You could try a workaround by allowing 0 for the optional parameter and loading all items in this case, as described here.

However, I'd recommend going with two different routes here to match everything you want:

api/lists/items
api/lists/{id?}/items

answered Jun 27, 2018 at 9:42

Bert H

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TalESid · Accepted Answer · 2018-06-27 09:40:24Z

3

You have to give default value for optional parameter in the controller:

Route

Route::get('api/lists/{id?}/items', 'ListsController@getListItems');

ListsController

public function getListItems($id = null) {
    ---your code----
}

Reference

answered Jun 27, 2018 at 9:40

TalESid

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2 Comments

Radical_Activity Over a year ago

This solution is not working because the route is not even found.

blank94 Over a year ago

This is not the solution because first of all laravel needs to find the route and /api/lists/items does not match with any of routes so it goes to 404 page

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