Check if the given value exist in another array?

Question

I have an array with some values as below:

$array1 =  [
    0 => "year",
    1 => "month"
];

I make a loop to this array and check if its value exist in following array.

array:3 [
  0 => array:3 [
    "name" => "year"
    "mandatory" => true
    "type" => "integer"
  ]
  1 => array:3 [
    "name" => "month"
    "mandatory" => true
    "type" => "integer"
  ]
  2 => array:3 [
    "name" => "id"
    "mandatory" => false
    "type" => "integer"
  ]
]

If if exists then I have to return array something like this

array[
   "year" => [
        "mandatory" => true
        "type" => "integer"
   ],
  "month" => [
        "mandatory" => true
        "type" => "integer"
   ],
]

This is the code so far I have tried.

$keys = array_keys($params);
$fields = $config["fields"];

$finalArr = array();
foreach($keys as $key) {
    if(in_array($key, array_column($fields, "name"))) {
        $finalArr[$key] = array();
    }
    $finalArr[$key][] = $fields;
}

But this returns all the records.

Can anybody help me.

All 3 items from the first array are all in the second, so why are you expecting only 1 element? Doesn't make any sense.. — Naruto
– Naruto, Commented Jun 25, 2019 at 8:49
Later I can use this finalArray where I can simply check by the key " year" and "month" — user1687891
– user1687891, Commented Jun 25, 2019 at 8:55

u_mulder · Accepted Answer · 2019-06-25 08:57:25Z

1

Iterate over your $fields and check if field's name exists in $keys:

foreach ($fields as $field) {
    if (in_array($field['name'], $keys)) {
        $finalArr[$field['name']] = $field;
    }
}

answered Jun 25, 2019 at 8:57

u_mulder

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