Laravel/Lumen route optional url query parametrers

Question

In Lumen I have to get the url first segment as a $source property and all other parts as a $path. It is solved by this:

Route::get('/{source}/{path:.*}', 'HomeController@index');

By this the /database/path/to/folder URL will be parsed as the $source = 'database'; and the $path = 'path/to/folder'; It's great!

But what when I would have optional query parameters too, for example: /database/path/to/folder?attr1=foo&attr2=bar

How can I define to get the whole query part in a property as a route parameter?

Chin Leung · Accepted Answer · 2019-10-14 14:14:11Z

2

Since they are optional and it is a query string, you do not have to define them in your route registration.

You can simply pass them when you generate the url. For instance:

Route::get('/{source}/{path:.*}', [
    'as' => 'home',
    'uses' => 'HomeController@index'
]);

Then you could do:

route('home', [
    'source' => 'database',
    'path' => 'path/to/folder',
    'attr1' => 'foo',
    'attr2' => 'bar'
]);

And the output would be:

http://example.com/database/path/to/folder?attr1=foo&attr2=bar

Update

Since you want to put all into a route parameter, you could achieve the same like this:

Route::get('{source}/{path:[a-z0-9/]+}[/{query:[a-z0-9=&]+}]', [
    'as' => 'home',
    'uses' => 'HomeController@index'
]);

Then you would generate the route like this:

route('home', [
    'source' => 'database',
    'path' => 'path/to/folder',
    'query' => 'attr1=foo&attr2=bar'
]);

And the output would be:

http://example.com/database/path/to/folder/attr1=foo&attr2=bar`

edited Oct 14, 2019 at 14:14

answered Oct 11, 2019 at 13:59

Chin Leung

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7 Comments

szatti1489 Over a year ago

Thanks @chin, it would be great, but in my case all the parameters are fully could be anything. I have to find out them dynamically. They name and they number too is could be anything.

Chin Leung Over a year ago

What do you mean @szatti1489? Where's the problem?

szatti1489 Over a year ago

The problem is that I don't know nor the names neither its number exactly. This is why I would get the whole query part into a variable to able to be parsed in php.

Chin Leung Over a year ago

@szatti1489 Please have a look at my updated answer :)

szatti1489 Over a year ago

Thanx a lot, It looks much better! My last problem is that I cannot use the where() method in route since I use Lumen actually. Do you have an ide how could the optional query part be separated from the optional path part? It could be something like this but of course it doesn't work due to the ? mark: Route::get('/{source}/{path:.*}?{query:.*}', 'HomeController@index');

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