How to make a case return a different value if a variable is true in swift?

Question

I was wondering if I could have a case statement return a different value if a variable was true or false.

var variable = false
enum enumeraton {
    case thing
    var value: Int {
        switch self {
        case .thing:
            if variable = true {
                return 1
            }else {
                return 2
            }
        }
    }
}

is there anyway to do this?

Yes you can. You just need to access "Variable" from where you call value. So maybe make a function (func value(withVariable: Bool) -> Int), or access it from the method (a singleton?) — Larme
– Larme, Commented May 6, 2021 at 14:09
Shouldn't your if-else be if variable == true you seem to be missing an equals sign in the condition — Andrew
– Andrew, Commented May 6, 2021 at 14:10

Joakim Danielson · Accepted Answer · 2021-05-06 14:37:38Z

2

Depending on how you want to treat variable there are different solutions. If you want to read the value of variable when creating your enum variable/property you can use an associated value with the enum

var variable = false
enum Enumeraton {
    case thing(Bool)
    var value: Int {
        switch self {
        case .thing(let flag):
            return flag ? 1 : 2
        }
    }
}

let enumValue: Enumeraton = .thing(variable)
print(enumValue.value)

But if you want to read variable over time then a function that takes the boolean as an argument is better

enum Enumeraton {
    case thing

    func value(for flag: Bool) -> Int {
        guard self == .thing else { return 0 } // or some other action
        return flag ? 1 : 2
    }
}

let enumValue: Enumeraton = .thing
print(enumValue.value(for: variable))

answered May 6, 2021 at 14:37

Joakim Danielson

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Comments

Moritz Schaub · Accepted Answer · 2021-05-06 14:26:33Z

1

Here is a solution that could work. Tested with Xcode 12.5 and Swift 5.4

var variable = false
enum enumeraton {
    case thing
    case other
    var value: Int {
        switch self {
        case .thing:
            if variable {
                return 1
            } else {
                return 2
            }
        case .other:
            return 0
        }
    }
}

let foo = enumeraton.thing
print(foo.value) //prints 2

variable = true
print(foo.value) //prints 1

answered May 6, 2021 at 14:26

Moritz Schaub

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