Python function not returning true or false

Question

This is a simple function that checks the values entered by the user and returns true if x is a multiple of y, if not it returns false. When I run the code, it prompts the user to enter a number for x and y but does not display whether it is true or false. What am I doing wrong?

def is_multiple(x, y):
    if (y % x) == 0:
        print("True")
    else:
        print("False")

x = int(input("enter any number :"))
y = int(input("enter a multiple :"))

(Also, your function returns None; it writes the string True or the string False to standard output.) — chepner
– chepner, Commented Feb 28, 2022 at 15:49

chepner · Accepted Answer · 2022-02-28 15:46:43Z

1

You have to call the function after you get the arguments.

def is_multiple(x, y):
    if y % x == 0:
        print("True")
    else:
        print("False")


# Using different names to stress the difference between
# function parameters and function arguments.
n = int(input("enter any number :"))
m = int(input("enter a multiple :"))
is_multiple(n, m)

answered Feb 28, 2022 at 15:46

chepner

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Comments

GHOST-34 · Accepted Answer · 2022-02-28 15:51:18Z

1

As others have mentioned, you have to call the function.

Add this at the end:

is_multiple(x, y)

You could make your function much more useful by doing this however:

def is_multiple(x, y):
if (y % x) == 0:
    return True
else:
    return False

x = int(input("enter any number :"))
y = int(input("enter a multiple :"))
print(is_multiple(x, y))

Now your function actually returns a value that you can use however you'd like. In this case, it is printing the returned value.

answered Feb 28, 2022 at 15:51

GHOST-34

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Comments

Palani · Accepted Answer · 2022-02-28 15:47:37Z

0

call the function which you declared above

is_multiple(x,y)

answered Feb 28, 2022 at 15:47

Palani

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